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Lukecrayonz

  • 2 years ago

How many kilograms are in 4 moles of Na2CO3?

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  1. zbay
    • 2 years ago
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    Whats the molar mass of that? I don't have a periodic table so I keep asking

  2. Lukecrayonz
    • 2 years ago
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    zbay, http://www.webqc.org/mmcalc.php for future use:)

  3. Lukecrayonz
    • 2 years ago
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    Molar mass of Na2CO3 is 105.9886 g/mol

  4. zbay
    • 2 years ago
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    \[4 mole Na_2CO_3(\frac{105.99 g Na_2CO_3}{1 mole Na_2CO_3})(\frac{1 kg}{1000 g })=.424 kg Na_2CO_3\]

  5. zbay
    • 2 years ago
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    Is the equation loading or does it look all crazy for you?

  6. Lukecrayonz
    • 2 years ago
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    Looks fine:)

  7. zbay
    • 2 years ago
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    ok cool

  8. anubhuti
    • 2 years ago
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    let me first tell u how to calculate molar mass ok? u need to find of Na2CO3 so add the molar masses of the elements together multiplying them with their respective subscripts so here it goes like this Na= 23 C=12 O=16 so Na2CO3=2(23)+12+3(16)=46+12+48=96

  9. Xishem
    • 2 years ago
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    \[46+12+48=106\]

  10. anubhuti
    • 2 years ago
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    now 1 mole of sodium carbonate has 96 grams so 4 moles will have 4x106=424 oh yeah sry

  11. anubhuti
    • 2 years ago
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    oops sry now that means one mole of Na2CO3 will have 106 grams

  12. anubhuti
    • 2 years ago
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    thanks

  13. Xishem
    • 2 years ago
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    To get the final answer, you need to convert to kg (:.

  14. anubhuti
    • 2 years ago
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    well that is easy enough... from here the question can b done by the asker himself yhe main question has been solved isnt it? even so the answer is .106 kg ok?

  15. Xishem
    • 2 years ago
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    Well, zbay has already answered the question. It's .424kg of Na_2CO_3

  16. anubhuti
    • 2 years ago
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    yeah...

  17. anubhuti
    • 2 years ago
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    hah i again forgot to multiply by 4 wat a shame yeah k the answer is .424 kg i m really sry

  18. Xishem
    • 2 years ago
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    Don't be sorry! We're all learning here.

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