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Lukecrayonz

How many kilograms are in 4 moles of Na2CO3?

  • 2 years ago
  • 2 years ago

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  1. zbay
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    Whats the molar mass of that? I don't have a periodic table so I keep asking

    • 2 years ago
  2. Lukecrayonz
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    zbay, http://www.webqc.org/mmcalc.php for future use:)

    • 2 years ago
  3. Lukecrayonz
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    Molar mass of Na2CO3 is 105.9886 g/mol

    • 2 years ago
  4. zbay
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    \[4 mole Na_2CO_3(\frac{105.99 g Na_2CO_3}{1 mole Na_2CO_3})(\frac{1 kg}{1000 g })=.424 kg Na_2CO_3\]

    • 2 years ago
  5. zbay
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    Is the equation loading or does it look all crazy for you?

    • 2 years ago
  6. Lukecrayonz
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    Looks fine:)

    • 2 years ago
  7. zbay
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    ok cool

    • 2 years ago
  8. anubhuti
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    let me first tell u how to calculate molar mass ok? u need to find of Na2CO3 so add the molar masses of the elements together multiplying them with their respective subscripts so here it goes like this Na= 23 C=12 O=16 so Na2CO3=2(23)+12+3(16)=46+12+48=96

    • 2 years ago
  9. Xishem
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    \[46+12+48=106\]

    • 2 years ago
  10. anubhuti
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    now 1 mole of sodium carbonate has 96 grams so 4 moles will have 4x106=424 oh yeah sry

    • 2 years ago
  11. anubhuti
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    oops sry now that means one mole of Na2CO3 will have 106 grams

    • 2 years ago
  12. anubhuti
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    thanks

    • 2 years ago
  13. Xishem
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    To get the final answer, you need to convert to kg (:.

    • 2 years ago
  14. anubhuti
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    well that is easy enough... from here the question can b done by the asker himself yhe main question has been solved isnt it? even so the answer is .106 kg ok?

    • 2 years ago
  15. Xishem
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    Well, zbay has already answered the question. It's .424kg of Na_2CO_3

    • 2 years ago
  16. anubhuti
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    yeah...

    • 2 years ago
  17. anubhuti
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    hah i again forgot to multiply by 4 wat a shame yeah k the answer is .424 kg i m really sry

    • 2 years ago
  18. Xishem
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    Don't be sorry! We're all learning here.

    • 2 years ago
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