anonymous
  • anonymous
Solve the system of equations using the elimination method. 3x-4y=0 2x-3y=-1
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
how do i solve this?
anonymous
  • anonymous
multiply the first equation by 2 and the 2nd equation by -3 and add them together
anonymous
  • anonymous
2(3x-4y=0) => 6x-8y=0 -3(2x-3y=-1)=>-6x+9y=3 adding them together give you y=3

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anonymous
  • anonymous
6x-8y=0-eqn1 6x-9y=-3-eqn2 eqn1-eqn2=>y=3 6x-24=0 6x=24 x=4
anonymous
  • anonymous
okay. got iy.
campbell_st
  • campbell_st
Label the equations 3x - 4y = 0 (1) and 2x - 3y = -1 (2) the 2 x (1) - 3 x (2) this will eliminate x as shown below 6x - 8y = 0 -6x+ 9y = -3 y = -3 hence y = -3 and sub into either equation to find x, x = 4
campbell_st
  • campbell_st
oops y = 3
anonymous
  • anonymous
okay. thanks you guys! i really appreciate it! :)

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