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\[=7(1)(\sin(7 \cdot 0))=7\sin(0)=7(0)=0\]

i don't understand high level math

so its 0?

all I understand is sin from triangle

yes it 0

did you really mean x->0?

watch the lanaguage

read the code of conduct

lim x→0 x^2 / sin^2 4x

i got it right :) and my bad buddy didnt know sucks was a bad word

so this changes thing since x->0 and not t

not that...

jsut be careful what you say to people..

well i think when you put it with that other word its bad

thats one i just did was a new one, that i dont get

\[\lim_{x \rightarrow 0}\frac{\sin^2(7t)}{t}=\frac{\sin^2(7t)}{t}\]

i thought you meant t->0 earlier

now that i know you actually meant x->0 this is correct

the one i did earlier had 7t sin^2.... but i just posted one that was like
lim x→0 x^2 / sin^2 4x

i'm confused

which one did you mean?
x->0 or t->0

i need help with the last one where3 x -->0

i been talking about the first one you put up

t->0 or x->0?

the first one is right you did great!

you said x->0
i did the problem for t->0 not x->0

|dw:1328073227704:dw|

i did this problem that you posted first fro t->0

not x->0

i thought you meant t->0

i was t on that one

t->0?

yeH

ok! then the first way i did it was correct

but the new one has x -> 0 x^2/ sin^2 * 4x

look for 4x/sin(4x)
this will go to 1 as x->0

so its 1?

4x/(sin(4x))->1 as x->0
so look for 4x/sin(4x)

im confuse :/

\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1\]

use this

so now i solve for x?

there is no equation we aren't solving for x
we are trying to find the limit

look for what i told you to look for

so i plug in 1 in x's place

\[=\lim_{x \rightarrow 0}\frac{4x}{4 \sin(4x)} \cdot \frac{4x}{4 \sin(4x)} \]

no use what i told you to use

\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1 \]
remember this!

is the answer 1/4

|dw:1328073897366:dw|

|dw:1328073931961:dw|

what do those circled things go to?

the problem right?, the original one

\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1\]

so what do those circled things go to?

|dw:1328074125358:dw|

they go to 1

so what do we have ?

okay, I see that now, so do i add the two fours thats left over together? or just 1 +1

this is multiplication
there is no addition here

raginsquirrel says its your bday

so 4 *4

and both of those 4's are on bottom right?

1/16

yes

wow... youre a genius, my teaher is foreign so i cant understand her, and she doesnt ever explain

so how about 1- cos9x/ sin 9x bc cos and sine are oppositeees arent they?