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anonymous
 4 years ago
what is the limit of lim X>0 sin^2 * 7t / t
anonymous
 4 years ago
what is the limit of lim X>0 sin^2 * 7t / t

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{t \rightarrow 0}\frac{\sin^2(7t)}{t}=\lim_{t \rightarrow 0}\frac{\sin(7t) \cdot \sin(7t)}{t}\] \[\lim_{t \rightarrow 0}\frac{\sin(7t)}{t} \cdot \sin(7t)=7 \cdot \lim_{t \rightarrow 0}\frac{\sin(7t)}{7t} \cdot \lim_{t \rightarrow 0}\sin(7t)\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[=7(1)(\sin(7 \cdot 0))=7\sin(0)=7(0)=0\]

pokemon23
 4 years ago
Best ResponseYou've already chosen the best response.1i don't understand high level math

pokemon23
 4 years ago
Best ResponseYou've already chosen the best response.1all I understand is sin from triangle

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1did you really mean x>0?

pokemon23
 4 years ago
Best ResponseYou've already chosen the best response.1read the code of conduct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lim x→0 x^2 / sin^2 4x

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1yeah just to be careful i wouldn't say that so you also meant sin^2 * 7t or sin^2(7t) because sin^2 * 7t doesn't make sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got it right :) and my bad buddy didnt know sucks was a bad word

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1so this changes thing since x>0 and not t

pokemon23
 4 years ago
Best ResponseYou've already chosen the best response.1jsut be careful what you say to people..

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1well i think when you put it with that other word its bad

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{\sin^2(7t)}{t}\] so this really was the problem now what I thought it was

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats one i just did was a new one, that i dont get

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{\sin^2(7t)}{t}=\frac{\sin^2(7t)}{t}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1i thought you meant t>0 earlier

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1now that i know you actually meant x>0 this is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the one i did earlier had 7t sin^2.... but i just posted one that was like lim x→0 x^2 / sin^2 4x

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1which one did you mean? x>0 or t>0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need help with the last one where3 x >0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1i been talking about the first one you put up

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the first one is right you did great!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1you said x>0 i did the problem for t>0 not x>0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328073227704:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1i did this problem that you posted first fro t>0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1i thought you meant t>0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1ok! then the first way i did it was correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but the new one has x > 0 x^2/ sin^2 * 4x

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1look for 4x/sin(4x) this will go to 1 as x>0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.14x/(sin(4x))>1 as x>0 so look for 4x/sin(4x)

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{x^2}{\sin^2(4x)}=\lim_{x \rightarrow 0}\frac{x}{\sin(4x)} \cdot \frac{x}{\sin(4x)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so now i solve for x?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1there is no equation we aren't solving for x we are trying to find the limit

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1look for what i told you to look for

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i plug in 1 in x's place

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[=\lim_{x \rightarrow 0}\frac{4x}{4 \sin(4x)} \cdot \frac{4x}{4 \sin(4x)} \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1no use what i told you to use

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1 \] remember this!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328073897366:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328073931961:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1what do those circled things go to?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the problem right?, the original one

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 0}\frac{4x}{\sin(4x)}=1\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1so what do those circled things go to?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328074125358:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, I see that now, so do i add the two fours thats left over together? or just 1 +1

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1this is multiplication there is no addition here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0raginsquirrel says its your bday

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1and both of those 4's are on bottom right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow... youre a genius, my teaher is foreign so i cant understand her, and she doesnt ever explain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so how about 1 cos9x/ sin 9x bc cos and sine are oppositeees arent they?
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