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anonymous
 4 years ago
lim x>0 1  cos9x / sin 9x
anonymous
 4 years ago
lim x>0 1  cos9x / sin 9x

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dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0you get 0/0 which is indeterminate. you need to use what is called L'Hopitals rule where you can differentiate the top and bottom and the limit will be the same > 9sin(9x)/9cos(9x) = tan(9x) lim x>0 tan(9x) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you! can you help me with another one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lim x→0 cos 9x − cos^2 *9x / 9x

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0same thing, take derivative of both top and bottom functions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0coooommmmmmmmeeeee bbbbaaaaacccckkkk
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