anonymous
  • anonymous
find the x-values that are solutions of the equation 5cot^2x-15=0
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
rearrange a little bit to make this easier \[5\cot^2 x=15 \rightarrow \cot^2 x = 3 \rightarrow \cos^2 x = 3\sin^2x\rightarrow \cos x = \sqrt{3} \sin x\] from here you're on your own
anonymous
  • anonymous
where did the sine come out of? i understand up to cot^2x=3
anonymous
  • anonymous
\[cot(x) = \frac{1}{tan(x)}~\text{and}~~ tan(x)=\frac{sin(x)}{cos(x)}\]

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