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anonymous
 4 years ago
Assume you have 6 dimes and 5 quarters (all distinct), and you select 5 coins.
Total ways selection can be made= 462
How many ways can the selection be made so that at least 4 coins are dimes?______________
anonymous
 4 years ago
Assume you have 6 dimes and 5 quarters (all distinct), and you select 5 coins. Total ways selection can be made= 462 How many ways can the selection be made so that at least 4 coins are dimes?______________

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.06x5x4x3  = 15 +7= 22 4x3x2x1 Is that right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.06*5*4*3*2*1 7*6*5*4*3*2*1  +  4*3*2*1*2*1 1*6*5*4*3*2*1

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.2Two separate cases: That would be the sum of the numbers of ways to choose exactly 4 dimes and then exactly 5 dimes.. C(6,4) times C(5,1) + C(6,5) times C(5, 0) = 81.

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.2I included the case of 6 dimes and messed up the first time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That did it direct.... awesome man

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is hard for me to id the cases in a lot of these

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 more i couldn't do from that section i am going to post.... thank you so much

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.2Ok, I'll look for it.
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