anonymous
  • anonymous
A student wants to buy 3 cds, but assume 5 cds feature the piano, 6 cds feature the trumpet, and 3 cds feature the saxaphone. I figured there are 364 ways for 3 cd's to be selected. In how many ways can the selection be made if cds featuring at least 2 different instruments are selected?_______________--
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Moving on to computing probabilities by using equally likely outcomes after this
anonymous
  • anonymous
haha
anonymous
  • anonymous
HOLY COW

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anonymous
  • anonymous
How does that happen
anonymous
  • anonymous
i can copy and paste them
anonymous
  • anonymous
if you cant see the first part of your solution
anonymous
  • anonymous
no
Directrix
  • Directrix
I'll try again. Patience is a good thing. :)
anonymous
  • anonymous
you dont have to I am considering moving on to some other stuff that i am not sure how to do at all
anonymous
  • anonymous
nope
anonymous
  • anonymous
i tried that earlier
Directrix
  • Directrix
I want to do it. You can move on to another problem while I work on this.
anonymous
  • anonymous
Your call man i have spent A LOT of time on these 27 questions our exam questions are coming directly from these Homework problems like this
anonymous
  • anonymous
I will post another shortly im sure
Directrix
  • Directrix
Here's where I messed up. The problem is at least 2 different instruments are selected? I calculated at least 2 of the SAME instrument.
anonymous
  • anonymous
yes that is correct
anonymous
  • anonymous
i need to sign off for a moment bu i will be back in 5-10 mins at the most
Directrix
  • Directrix
Okay, no rush. I just cleaned up my work area for my next take on this problem.
anonymous
  • anonymous
im back around
Directrix
  • Directrix
P = Piano, S = Sax, T = Trumpet Of the 3 cds we are buying, 2 could be of the same instrument and 1 of another instrument. I see the following cases: PPT, PTT and PPS, PSS, and TTS, TSS. Do you see others before we calculate?
anonymous
  • anonymous
I don't
Directrix
  • Directrix
PPT, PTT PPT==> C(5,2) times C(6,1) = 60 PTT ==> C(5,1) times C(6,2) = 75 Subtotal 1: 135 (Not Finished)
Directrix
  • Directrix
PPS, PSS PPS ==>C (5,2) times C (3,1) = 30 PSS ==> C(5,1) times C(3,2) = 15 Subtotal 2: 45 (Not Finished)
Directrix
  • Directrix
TTS, TSS TTS==> C(6,2) times C(3,1) = 45 TSS ==> C(6,1) times C(3,2) = 18 Subtotal 3: 63 (Not Finished)
Directrix
  • Directrix
Answer: Total of Subtotals of cases: 135 + 45 + 63 = 243 ways.
Directrix
  • Directrix
CW, what about this answer of 243?
anonymous
  • anonymous
no it didnt work
Directrix
  • Directrix
What did we miss? By the way, is 314 the answer? I don't think so but tried something different.
anonymous
  • anonymous
no
Directrix
  • Directrix
We missed the case where all three are different such as P T S
anonymous
  • anonymous
hmmm
Directrix
  • Directrix
PTS C(5,1) times C(6,1) times C(3,1) = 90
Directrix
  • Directrix
So, the corrected answer is the Answer: Total of Subtotals (exactly 2 different cases plus all 3 differnt: : 135 + 45 + 63 + 90 =333. Answer:333
Directrix
  • Directrix
Bad news, CW?
anonymous
  • anonymous
what?
Directrix
  • Directrix
The answer -- 333. Right or wrong.
anonymous
  • anonymous
right hahaha
anonymous
  • anonymous
awesome man
anonymous
  • anonymous
ly cow
anonymous
  • anonymous
holy
Directrix
  • Directrix
Sure it's right? There may be another case out there, and we'll find it.
anonymous
  • anonymous
no that is correct
Directrix
  • Directrix
Okay, where are the other problems? "I will post another shortly im sure" you said.
anonymous
  • anonymous
yea i will in a moment
anonymous
  • anonymous
they are a different section

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