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anonymous

  • 4 years ago

How to do this 1 _______ √1-x^4

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  1. campbell_st
    • 4 years ago
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    is it \[1/\sqrt{1-x^4}\]

  2. anonymous
    • 4 years ago
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    x^4 has to be less than or equal to 1

  3. campbell_st
    • 4 years ago
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    and what do you have to do..?

  4. anonymous
    • 4 years ago
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    domain maybe?

  5. campbell_st
    • 4 years ago
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    x cannot be 1 or -1

  6. anonymous
    • 4 years ago
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    well the whole problem i will write out

  7. anonymous
    • 4 years ago
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    why can't it be you can have sqrt (0)

  8. anonymous
    • 4 years ago
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    1 is your answer

  9. anonymous
    • 4 years ago
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    well it probably was not √1-4^3

  10. anonymous
    • 4 years ago
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    there was never really a question

  11. anonymous
    • 4 years ago
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    but lemme get the whole problem out first

  12. anonymous
    • 4 years ago
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    oh the 1 is part of the equation..

  13. campbell_st
    • 4 years ago
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    I"ll ray rationalise... \[1/\sqrt{1-x^4} \times \sqrt{1 + x^4}/\sqrt{1 +x^4}\] gives \[\sqrt{1 - x^4}/(1-x^4)\]

  14. anonymous
    • 4 years ago
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    f(x) = x^3 - x^4

  15. anonymous
    • 4 years ago
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    thought he was saying how do you do this one:

  16. anonymous
    • 4 years ago
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    this is the whole problem

  17. anonymous
    • 4 years ago
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    was getting _____ √1-x^4 correct?

  18. anonymous
    • 4 years ago
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    where is that root sign coming from i'm still not sure what you're trying to do

  19. anonymous
    • 4 years ago
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    i just dont know if how i got it was correct entire problem f(x) = x^3 - x^4

  20. anonymous
    • 4 years ago
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    f(x)=x^3(1-x)

  21. anonymous
    • 4 years ago
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    that's just a function you can do ALOT of things with it?

  22. anonymous
    • 4 years ago
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    i am supposed to see if it is even odd or neither

  23. anonymous
    • 4 years ago
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    if it's odd f(x)=-f(-x)

  24. campbell_st
    • 4 years ago
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    well find f(-x) so f(-x) = (-x)^3 - (-x)^4 = -x^3 - x^4 if a function is even f(-x) = f(x) if odd f(-x) = -f(x) in your question the function is neither odd nor even for the above reason

  25. anonymous
    • 4 years ago
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    like he said..

  26. anonymous
    • 4 years ago
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    lol

  27. anonymous
    • 4 years ago
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    tyvm ppls

  28. anonymous
    • 4 years ago
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    :)

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