How to do this 1 _______ √1-x^4

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How to do this 1 _______ √1-x^4

Mathematics
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is it \[1/\sqrt{1-x^4}\]
x^4 has to be less than or equal to 1
and what do you have to do..?

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Other answers:

domain maybe?
x cannot be 1 or -1
well the whole problem i will write out
why can't it be you can have sqrt (0)
1 is your answer
well it probably was not √1-4^3
there was never really a question
but lemme get the whole problem out first
oh the 1 is part of the equation..
I"ll ray rationalise... \[1/\sqrt{1-x^4} \times \sqrt{1 + x^4}/\sqrt{1 +x^4}\] gives \[\sqrt{1 - x^4}/(1-x^4)\]
f(x) = x^3 - x^4
thought he was saying how do you do this one:
this is the whole problem
was getting _____ √1-x^4 correct?
where is that root sign coming from i'm still not sure what you're trying to do
i just dont know if how i got it was correct entire problem f(x) = x^3 - x^4
f(x)=x^3(1-x)
that's just a function you can do ALOT of things with it?
i am supposed to see if it is even odd or neither
if it's odd f(x)=-f(-x)
well find f(-x) so f(-x) = (-x)^3 - (-x)^4 = -x^3 - x^4 if a function is even f(-x) = f(x) if odd f(-x) = -f(x) in your question the function is neither odd nor even for the above reason
like he said..
lol
tyvm ppls
:)

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