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anonymous

  • 4 years ago

A mechanical engineer bought 24 boxes of screws for P2200. There were three types of screws bough. Screw A cost P300 per box, screw B costs P150 per box and screw C costs P50 per box. How many boxes of each screw did he buy?

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  1. anonymous
    • 4 years ago
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    x= number of screw A boxes y=number of screw B boxes z=number of screw C boxes x+y+z=24 300x+150y+50z=2200 Use substitution, elimination, or any other method you'd like and you'll get the solution XD

  2. anonymous
    • 4 years ago
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    A one Mathematica statement solution is attached.

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