anonymous
  • anonymous
an automobile accelerates from rest at 1+ 3* sqrt (t) mph/sec for 9 seconds. What is the velocity after 9 seconds?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1+3sqrt(9) 1+3(3) 1+9 10mph
Xishem
  • Xishem
^ Wouldn't this find the acceleration at time t, not the velocity?
Xishem
  • Xishem
*time 9s

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More answers

anonymous
  • anonymous
Good point Xishem... I wondered about that too, but I can't tell from the question X(
Xishem
  • Xishem
Would integrating the function from 0 to 9 give the correct answer?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Hm, when the problem states it like that... does it mean that the velocity is the function 1 + 3*(t) or the acceleration?
anonymous
  • anonymous
the function is of acceleration
anonymous
  • anonymous
so its integral will be velocity
anonymous
  • anonymous
It means acceleration....yeah, Xishem, you're right, this will require integration
anonymous
  • anonymous
Yeah, the book says mph/sec.. how should it be stated if it was giving the velocity?
anonymous
  • anonymous
(t+6t^(3/2)) from 0-->9
anonymous
  • anonymous
i would change either the hours to seconds or vice versa
anonymous
  • anonymous
so your answer can be in the form mps or mph
anonymous
  • anonymous
this can be done by dimensional analysis
dumbcow
  • dumbcow
i get v(t) = t + 2t*sqrt(t) v(9) = 9 +2*9*sqrt(9) = 63 mph
anonymous
  • anonymous
integral of sqrt (t) = [2t^(3/2)]/3 Multiply that by the 3 constant.. = 2t^(3/2) am I doing something wrong? I can't get sqrt (t)
anonymous
  • anonymous
it's the same thing... 2t*t^(1/2)=2t^(3/2)
anonymous
  • anonymous
Oh I see. I would have never though of to do that... makes calculations so much easier, haha.

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