A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A group of 1000 patients each diagnosed with a certain disease is being analyzed with regard to the disease symptoms present. The symptoms are labeled A,B,and C, and each patient has at least one symptom. Also,
900 have either symptom A or B (or both)
900 have either symptom A or C (or both)
800 have either symptom B or C (or both)
650 have symptom A
500 have symptom B
550 have symptom C
Determine:
1. The number who had both symptoms A and B
2. The number who had either symptom A or B (or both) but not C
3. The number who had all three symptoms
I cant seem to figure this out..
anonymous
 4 years ago
A group of 1000 patients each diagnosed with a certain disease is being analyzed with regard to the disease symptoms present. The symptoms are labeled A,B,and C, and each patient has at least one symptom. Also, 900 have either symptom A or B (or both) 900 have either symptom A or C (or both) 800 have either symptom B or C (or both) 650 have symptom A 500 have symptom B 550 have symptom C Determine: 1. The number who had both symptoms A and B 2. The number who had either symptom A or B (or both) but not C 3. The number who had all three symptoms I cant seem to figure this out..

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01. (just A + just B)(900 have either symptom A or B (or both)= 250

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what does your number 2 mean?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328113317366:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you continue this pattern tho, and 500 have B, your already at 500 right? so that leavesno one having all three or just B? That is why I am confused. PLEASE HELP :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i'm thinking............

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.2You can apply the principle of inclusion/exclusion. For 1, \(A \cup B = A+ B  A \cap B \) => \(A \cap B = A+ B  A \cup B \) =650+500900=250 Similarly \(B \cap C = B+ C  B \cup C \) = 500+550900=150 and \(C \cap A = C+ A  C \cup A \) = 550+650800=400 For 2, The answer is in the given data. For 3, \(A \cup B \cup C = A+ B + C  A \cap B B \cap C C \cap A + A\cap B \cap C \) which means \(A \cap B \cap C = A \cup B \cup C  A B  C + A \cap B+ B \cap C+ C \cap A \) =1000650500550+250+150+400 = 100 For more information, see http://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0omg. i didn't mentioned that all of the patients are 1000
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.