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anonymous

  • 4 years ago

to apply herbicide to a large field she must mix a solution of 67% herbicide with a solution of 46% herbicide to form 42 liters of a 55%solution.how much the 67%solution must they use ? A.23L B.18L C.34L D35L

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  1. anonymous
    • 4 years ago
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    B

  2. anonymous
    • 4 years ago
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    can you tell me the equation of how to solve it

  3. anonymous
    • 4 years ago
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    ok..

  4. anonymous
    • 4 years ago
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  5. anonymous
    • 4 years ago
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    I used this web side to solve eq. http://math.cowpi.com/systemsolver/2x2.html

  6. Mertsj
    • 4 years ago
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    x= liters of 67% solution 42-x= liters of 46% solution .67x+.46(42-x)=.55(42) Multiply both sides by 100 to get rid of decimal points: 67x+46(42-x)=55(42) 67x+1932-46x=2310 21x=378 x=18 liters of 67% solution 42-x=24 liters of 46% solution

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