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anonymous
 4 years ago
What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ?
Answer:
A)4, 2, or 0
B)2 or 0
C)3 or 1
D)7, 5, 3, or 1
anonymous
 4 years ago
What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ? Answer: A)4, 2, or 0 B)2 or 0 C)3 or 1 D)7, 5, 3, or 1

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Find f(x) first. Can you do that?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1It is very difficult to help you if you won't answer me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry im trying to multitask

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and idk how to find f(x):/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so you would subtract everything?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02) f(x) = 2x^7 + 2x^6 + 7x^5 + 7x^4  4x^3 + 4x^2 f(x) = 2x^7 + 2x^5  7x^5 + 7x^4 + 4x^3 + 4x^2 There are 3 changes of sign in f(x), which means there can be possibly either 3 negative zeros or just 1 negative zero. So the answer would be B.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[f(x)=2(x)^7+2(x)^6+7(x)^5+7(x)^4+4(x)^3+4(x)^2\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Ok kdwndr wants to help you now. Good bye.
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