anonymous
  • anonymous
What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ? Answer: A)4, 2, or 0 B)2 or 0 C)3 or 1 D)7, 5, 3, or 1
Mathematics
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anonymous
  • anonymous
What are the possible number of negative zeros of f(x) = –2x^7 + 2x^6 + 7x^5 + 7x^4 + 4x^3 + 4x^2 ? Answer: A)4, 2, or 0 B)2 or 0 C)3 or 1 D)7, 5, 3, or 1
Mathematics
chestercat
  • chestercat
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Mertsj
  • Mertsj
Find f(-x) first. Can you do that?
Mertsj
  • Mertsj
It is very difficult to help you if you won't answer me.
anonymous
  • anonymous
sorry im trying to multi-task

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anonymous
  • anonymous
and idk how to find f(-x):/
Mertsj
  • Mertsj
replace every x with -x
anonymous
  • anonymous
so you would subtract everything?
anonymous
  • anonymous
2) f(x) = 2x^7 + 2x^6 + 7x^5 + 7x^4 - 4x^3 + 4x^2 f(-x) = -2x^7 + 2x^5 - 7x^5 + 7x^4 + 4x^3 + 4x^2 There are 3 changes of sign in f(-x), which means there can be possibly either 3 negative zeros or just 1 negative zero. So the answer would be B.
anonymous
  • anonymous
Sorry, C
Mertsj
  • Mertsj
\[f(-x)=-2(-x)^7+2(-x)^6+7(-x)^5+7(-x)^4+4(-x)^3+4(-x)^2\]
Mertsj
  • Mertsj
Ok kdwndr wants to help you now. Good bye.
anonymous
  • anonymous
Thank you:)

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