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anonymous

  • 4 years ago

Given points P(2,-1), Q(-4, 2), and M(5,3), find coordinates of a point K such that MK is perpendicular to PQ? Help Please !!

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  1. anonymous
    • 4 years ago
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    I didn't compute it, but here's what you can do. Suppose (a,b) is the point K. Find the line that goes through the points M and K and its slope. If MK _|_ PQ, then their line slopes are inverse proportional and anti simetric.

  2. anonymous
    • 4 years ago
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    ?

  3. anonymous
    • 4 years ago
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    What don't you understand?

  4. anonymous
    • 4 years ago
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    linear equation of PQ is (y-y1)/y2-y1)=(x-x1)/(x2-x1) so it's y=(-1/2)x if you wanna have a perpendicular line their slope must be negative and reverse m1*m2=-1 so the slope must be 2 if you have the slope and a point the linear equation is (y-y1)=m(x-x1) so it's (y-2)=2(x-5) so y=2x-7

  5. anonymous
    • 4 years ago
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    but there aren't any line that goes through M and be perpendicular of PQ here

  6. anonymous
    • 4 years ago
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    Thanks

  7. anonymous
    • 4 years ago
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    |dw:1328118401845:dw|

  8. phi
    • 4 years ago
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    do you know how to find the equation of a line given two points ? if so find the equation of the line through points P and Q can you find the equation of a line given a slope and a point? If so, find the equation of the line through point M, given a slope= -1/m where m is the slope of the line through points P,Q (but see above, because amir found it for you) Given the equations of two different lines, can you find where the intersect? hint: if you have \[ y= m_1 x+b_1 and y= m_2 x + b_2 \] set the y values equal to each other and solve for x \[ m_1 x+b_1 = m_2 x + b_2 \]

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