Solution to PS3 problem 1 recursion ## slices the target each time a match is found and calls the function again ## with the new slice ## uses a counter to keep track of how many times a match is found. ## returns the counter to the recursive call from string import * def match(t,k): here= find(t,k) count=0 if find(t,k) >=0: count+=1 count = count + match(t[here+1:],k) return count target1 = 'atgacatgcacaagtatgcat' target2 = 'atgaatgcatggatgtaaatgcag' # key strings key10 = 'a' key11 = 'atg' key12 =

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Solution to PS3 problem 1 recursion ## slices the target each time a match is found and calls the function again ## with the new slice ## uses a counter to keep track of how many times a match is found. ## returns the counter to the recursive call from string import * def match(t,k): here= find(t,k) count=0 if find(t,k) >=0: count+=1 count = count + match(t[here+1:],k) return count target1 = 'atgacatgcacaagtatgcat' target2 = 'atgaatgcatggatgtaaatgcag' # key strings key10 = 'a' key11 = 'atg' key12 =

MIT 6.00 Intro Computer Science (OCW)
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Good Job skibum!Thanks for posting!

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