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anonymous

  • 4 years ago

Two 10-cm-long thin glass rods uniformly charged to + 10\;{\rm nC} are placed side by side, 4.0 cm apart. What are the electric field strengths E_1, E_2, and E_3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?

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  1. anonymous
    • 4 years ago
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    idk what my problem is. i know at 2cm E is 0. so to find E_1, i calculated by getting E at r=0.01 and subtracted r=.03

  2. anonymous
    • 4 years ago
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    i didn't think i would use the formula for infinite length rods since it's only 10cm

  3. JamesJ
    • 4 years ago
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    ok. Then you'll need this: http://online.cctt.org/physicslab/content/phyapc/lessonnotes/Efields/EchargedRods.asp

  4. JamesJ
    • 4 years ago
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    Now just plug away.

  5. anonymous
    • 4 years ago
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    i did!! i meant i used r^2=.01^2+.05^2. or am i suppose to use r=.01?

  6. JamesJ
    • 4 years ago
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    In your problem, L = 10 cm, a = 5 cm. Then what varies for each rod in each scenario is the perpendicular distance b.

  7. anonymous
    • 4 years ago
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    i did it just the way the formula is laid out and got 1.76*10^5 but the answer was 1.25*10^5...i think i see why it's 2 times charge density...

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