## anonymous 4 years ago The graph of which quadratic equation has a vertex of (–2, –1)?

1. anonymous

A.y = (x – 2)2 – 1 B.y = (x + 1)2 – 2 C.y = (x + 2)2 – 1 D.y = (x – 1)2 – 2

2. anonymous

$ax^2+bx+c$ $(\frac{-b}{2a},f(\frac{-b}{2a}))$ Looking at your options, choice C looks most likely for -b/2a to = -2 Expand: $x^2+4x+4-1=x^2+4x+3$ -b/(2a)=-4/2(1)=-2 $f(-2)=(-2)^2+4(-2)+3=4-4+3=-1$ Therefore; option C is the answer.