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anonymous
 4 years ago
3kHC2O4.H2O=
MOLAR MASS
anonymous
 4 years ago
3kHC2O4.H2O= MOLAR MASS

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is the same as the previous problem you posted. Try going through a similar process as the one I showed there, and see what answer you come up with.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please help me,i got 438.3 as my molar mass here,just wanna be sure if my solving is right cos i will be doing a long calculation of limiting reagent with it.if i miss the molar mass,the whole thing will be wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just want to make sure I'm reading it correctly. The formula is this, correct?\[3KHC_2O_4·H_2O\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got 402.53g*mol^{1}. Could you go ahead and show your work and I can see where you got off?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03*(39.1+1+24+64+2+16)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There aren't 3mols of the H2O, unless the equation is actually written like this...\[3(KHC_2O_4·H_2O)\]Otherwise, if it's like I wrote it above, it the math should like something like this...\[3*(39.1+1+24+64)+1*(2+16)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh! ok,i now see my mistake thanks
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