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anonymous

  • 4 years ago

3kHC2O4.H2O= MOLAR MASS

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  1. Xishem
    • 4 years ago
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    This is the same as the previous problem you posted. Try going through a similar process as the one I showed there, and see what answer you come up with.

  2. anonymous
    • 4 years ago
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    please help me,i got 438.3 as my molar mass here,just wanna be sure if my solving is right cos i will be doing a long calculation of limiting reagent with it.if i miss the molar mass,the whole thing will be wrong

  3. Xishem
    • 4 years ago
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    I just want to make sure I'm reading it correctly. The formula is this, correct?\[3KHC_2O_4·H_2O\]

  4. anonymous
    • 4 years ago
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    yeah exactly

  5. Xishem
    • 4 years ago
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    I got 402.53g*mol^{-1}. Could you go ahead and show your work and I can see where you got off?

  6. anonymous
    • 4 years ago
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    ok

  7. anonymous
    • 4 years ago
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    3*(39.1+1+24+64+2+16)

  8. anonymous
    • 4 years ago
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    =438.3g/mol

  9. Xishem
    • 4 years ago
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    There aren't 3mols of the H2O, unless the equation is actually written like this...\[3(KHC_2O_4·H_2O)\]Otherwise, if it's like I wrote it above, it the math should like something like this...\[3*(39.1+1+24+64)+1*(2+16)\]

  10. anonymous
    • 4 years ago
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    oh! ok,i now see my mistake thanks

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