3kHC2O4.H2O= MOLAR MASS

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3kHC2O4.H2O= MOLAR MASS

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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This is the same as the previous problem you posted. Try going through a similar process as the one I showed there, and see what answer you come up with.
please help me,i got 438.3 as my molar mass here,just wanna be sure if my solving is right cos i will be doing a long calculation of limiting reagent with it.if i miss the molar mass,the whole thing will be wrong
I just want to make sure I'm reading it correctly. The formula is this, correct?\[3KHC_2O_4·H_2O\]

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yeah exactly
I got 402.53g*mol^{-1}. Could you go ahead and show your work and I can see where you got off?
ok
3*(39.1+1+24+64+2+16)
=438.3g/mol
There aren't 3mols of the H2O, unless the equation is actually written like this...\[3(KHC_2O_4·H_2O)\]Otherwise, if it's like I wrote it above, it the math should like something like this...\[3*(39.1+1+24+64)+1*(2+16)\]
oh! ok,i now see my mistake thanks

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