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anonymous

  • 4 years ago

y = ^3 square root 7x -9 help..i'm stumped :(

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  1. anonymous
    • 4 years ago
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    What is it exactly that you want?

  2. anonymous
    • 4 years ago
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    do you mean the cube of square root of (7x-9)? y = (7x-8)^(3/2)

  3. anonymous
    • 4 years ago
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    I think he means \(y=\sqrt[3]{7x-9}.\)

  4. anonymous
    • 4 years ago
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    and as anwar said what do u want to do qith it?

  5. anonymous
    • 4 years ago
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    AnwarA has the correct equation. The question is what is the inverse of this equation. f^-1 = ??

  6. anonymous
    • 4 years ago
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    cube both sides: y^3 = 7x - 9 7x = y^3 + 9 x = (y^3 -9) / 7 replace y by x: f^-1 = (x^3 - 9) / 7

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