y = ^3 square root 7x -9 help..i'm stumped :(

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y = ^3 square root 7x -9 help..i'm stumped :(

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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What is it exactly that you want?
do you mean the cube of square root of (7x-9)? y = (7x-8)^(3/2)
I think he means \(y=\sqrt[3]{7x-9}.\)

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and as anwar said what do u want to do qith it?
AnwarA has the correct equation. The question is what is the inverse of this equation. f^-1 = ??
cube both sides: y^3 = 7x - 9 7x = y^3 + 9 x = (y^3 -9) / 7 replace y by x: f^-1 = (x^3 - 9) / 7

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