## A community for students. Sign up today

Here's the question you clicked on:

## anonymous 4 years ago Rewrite x^2-2x+8y + 25=0 in the form (x-h)^2=4p(y-k)

• This Question is Closed
1. anonymous

Please help!

2. PaxPolaris

$x^2-2x+8y + 25=0$$\implies x^2-2x=-8y - 25$$\implies x^2-2x+1=-8y - 25+1$$\implies \left( x-1 \right)^2=-8y - 24$$\implies \left( x-1 \right)^2=-8(y +3)$

3. PaxPolaris

$\huge\implies \left( x-1 \right)^2=4 \cdot (-2)\left[y-\left( -3 \right)\right]$

4. anonymous

Okay thank you. How can I decide what to do? I mean I never know what steps to take?

5. PaxPolaris

First move all the x terms on one side & all the non-x terms on the other... Then you need to add to both sides a number that would make the x side a perfect square. Generally if you have x^2+ bx you would add: $\left( \frac b2 \right)^2 or\ {b^2 \over 4}$

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy