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anonymous

  • 4 years ago

the lengths of the diagonals of a rhombus are 6 and 8 what is the length of the side of a rhombus

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  1. anonymous
    • 4 years ago
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    5

  2. anonymous
    • 4 years ago
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    how did you find that answer cuz the ? confused me

  3. campbell_st
    • 4 years ago
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    the diagonals intersect at right angles and bisect each other.... So you will have a right triangle with sides 3 and 4 respectively... you need to use pythagoras' theorem to find the length of the side of the rhombus(hypotenuse)

  4. anonymous
    • 4 years ago
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    |dw:1328135974747:dw|

  5. anonymous
    • 4 years ago
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    Yeap, the diagonals of the Rhombus bisect each other at right angles, so use pythagoras theorem

  6. anonymous
    • 4 years ago
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    Pythagorean theorem a^2+b^2=c^2 gives you 5 in the triangle i drew up there XD

  7. anonymous
    • 4 years ago
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    and as campbell says, the diagonals bisect each other.

  8. anonymous
    • 4 years ago
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    |dw:1328185481899:dw|

  9. anonymous
    • 4 years ago
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    i got 10 ?

  10. anonymous
    • 4 years ago
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    its worth remembering the 3-4-5 triangle is a right angled also multiples of the sides i e 6-8-10, 9-12-15 etc another one is 5-12-13 - saves you using pythagoras

  11. anonymous
    • 4 years ago
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    \[\sqrt{3^2+4^2}\]

  12. anonymous
    • 4 years ago
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    ohh you have to cut the number in half

  13. anonymous
    • 4 years ago
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    That's from Pythagoras theorem

  14. anonymous
    • 4 years ago
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    Yay, everyone XD

  15. anonymous
    • 4 years ago
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    Cheers, nice to be back at openstudy after a long gap

  16. anonymous
    • 4 years ago
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    i am glad to have people like you guys willing to help someone who is struggling in math

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