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anonymous

  • 4 years ago

given sec(theta)= 5... find cot(90-theta)

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  1. asnaseer
    • 4 years ago
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    do you know what sec(theta) represents in terms of cos(theta)?

  2. anonymous
    • 4 years ago
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    yesh.. it represents its recioprical

  3. anonymous
    • 4 years ago
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    pardon the spelling

  4. asnaseer
    • 4 years ago
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    :) thats ok - we all make mishtakes :D

  5. anonymous
    • 4 years ago
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    asnaseer why did u report me

  6. anonymous
    • 4 years ago
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    wlbrt316 were busy in here..

  7. asnaseer
    • 4 years ago
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    ok, so you know:\[\sec(\theta)=\frac{1}{\cos(\theta)}\]which means you now know:\[\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}\]

  8. anonymous
    • 4 years ago
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    great so now we know cos(theta). but i dont see how that helps us find cot(90-theta)

  9. asnaseer
    • 4 years ago
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    |dw:1328138885501:dw|

  10. asnaseer
    • 4 years ago
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    so if you now use the Pythagoras theorem to work out x, then you should be able to work out the answer to your question.

  11. anonymous
    • 4 years ago
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    still sort of lost

  12. anonymous
    • 4 years ago
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    i guess im trying to find theta

  13. asnaseer
    • 4 years ago
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    do you know how to work out the value of x?

  14. anonymous
    • 4 years ago
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    yeah its sqrroot of 24 i think

  15. asnaseer
    • 4 years ago
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    correct. so now do you know what \(\cot(\theta)\) is from the diagram above?

  16. asnaseer
    • 4 years ago
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    sorry, I meant \(\cot(90-\theta)\)

  17. anonymous
    • 4 years ago
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    1/sqrt24

  18. anonymous
    • 4 years ago
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    uhh

  19. asnaseer
    • 4 years ago
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    what you gave was the value of \(\cot(\theta)\), what would \(\cot(90-\theta)\) be?

  20. anonymous
    • 4 years ago
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    idk really

  21. asnaseer
    • 4 years ago
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    |dw:1328139244893:dw|

  22. anonymous
    • 4 years ago
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    wait

  23. anonymous
    • 4 years ago
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    isnt it sqrt 24/1

  24. asnaseer
    • 4 years ago
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    perfect - well done!

  25. anonymous
    • 4 years ago
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    ohh.. ok i think i get it. i wasnt visualizing it, my college prof. is a fluttering idiot pardod my french, and he's taking vicadon, and he doesnt explain anything. in fact so far he hasnt given us any notes.. he's just went through examples of things and walked us through them. but i appreciate the help

  26. anonymous
    • 4 years ago
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    lol.. fluddering

  27. asnaseer
    • 4 years ago
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    yw

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