given sec(theta)= 5... find cot(90-theta)

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given sec(theta)= 5... find cot(90-theta)

Mathematics
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do you know what sec(theta) represents in terms of cos(theta)?
yesh.. it represents its recioprical
pardon the spelling

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:) thats ok - we all make mishtakes :D
asnaseer why did u report me
wlbrt316 were busy in here..
ok, so you know:\[\sec(\theta)=\frac{1}{\cos(\theta)}\]which means you now know:\[\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}\]
great so now we know cos(theta). but i dont see how that helps us find cot(90-theta)
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so if you now use the Pythagoras theorem to work out x, then you should be able to work out the answer to your question.
still sort of lost
i guess im trying to find theta
do you know how to work out the value of x?
yeah its sqrroot of 24 i think
correct. so now do you know what \(\cot(\theta)\) is from the diagram above?
sorry, I meant \(\cot(90-\theta)\)
1/sqrt24
uhh
what you gave was the value of \(\cot(\theta)\), what would \(\cot(90-\theta)\) be?
idk really
|dw:1328139244893:dw|
wait
isnt it sqrt 24/1
perfect - well done!
ohh.. ok i think i get it. i wasnt visualizing it, my college prof. is a fluttering idiot pardod my french, and he's taking vicadon, and he doesnt explain anything. in fact so far he hasnt given us any notes.. he's just went through examples of things and walked us through them. but i appreciate the help
lol.. fluddering
yw

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