anonymous
  • anonymous
given sec(theta)= 5... find cot(90-theta)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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asnaseer
  • asnaseer
do you know what sec(theta) represents in terms of cos(theta)?
anonymous
  • anonymous
yesh.. it represents its recioprical
anonymous
  • anonymous
pardon the spelling

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asnaseer
  • asnaseer
:) thats ok - we all make mishtakes :D
anonymous
  • anonymous
asnaseer why did u report me
anonymous
  • anonymous
wlbrt316 were busy in here..
asnaseer
  • asnaseer
ok, so you know:\[\sec(\theta)=\frac{1}{\cos(\theta)}\]which means you now know:\[\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}\]
anonymous
  • anonymous
great so now we know cos(theta). but i dont see how that helps us find cot(90-theta)
asnaseer
  • asnaseer
|dw:1328138885501:dw|
asnaseer
  • asnaseer
so if you now use the Pythagoras theorem to work out x, then you should be able to work out the answer to your question.
anonymous
  • anonymous
still sort of lost
anonymous
  • anonymous
i guess im trying to find theta
asnaseer
  • asnaseer
do you know how to work out the value of x?
anonymous
  • anonymous
yeah its sqrroot of 24 i think
asnaseer
  • asnaseer
correct. so now do you know what \(\cot(\theta)\) is from the diagram above?
asnaseer
  • asnaseer
sorry, I meant \(\cot(90-\theta)\)
anonymous
  • anonymous
1/sqrt24
anonymous
  • anonymous
uhh
asnaseer
  • asnaseer
what you gave was the value of \(\cot(\theta)\), what would \(\cot(90-\theta)\) be?
anonymous
  • anonymous
idk really
asnaseer
  • asnaseer
|dw:1328139244893:dw|
anonymous
  • anonymous
wait
anonymous
  • anonymous
isnt it sqrt 24/1
asnaseer
  • asnaseer
perfect - well done!
anonymous
  • anonymous
ohh.. ok i think i get it. i wasnt visualizing it, my college prof. is a fluttering idiot pardod my french, and he's taking vicadon, and he doesnt explain anything. in fact so far he hasnt given us any notes.. he's just went through examples of things and walked us through them. but i appreciate the help
anonymous
  • anonymous
lol.. fluddering
asnaseer
  • asnaseer
yw

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