anonymous
  • anonymous
does anyone know why y'=2x, y(0)=0, y(1)=100 has no solution?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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JamesJ
  • JamesJ
If dy/dx = 2x, what is the general solution of that equation? It's y(x) = x^2 + C. Now is there ANY choice of the number C such that y(0) = 0 and y(1) = 100?
anonymous
  • anonymous
Ya general solution y=x^2 + c1 no problem. but the book says "Show that the problem has no solution. Is this an Initial value problem?" I don't how this statement can be correct when c can take on any value since it is arbitrary.
myininaya
  • myininaya
right you have a contradiction so there is no y with those conditions that satisfy the differential equation

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JamesJ
  • JamesJ
Given that y(x) = x^2 + c, you now what to find ONE value of c such that it both true that y(0) = 0 AND y(1) = 100 Does there exist one value of c such that both of those conditions are satisfied?
anonymous
  • anonymous
nope
JamesJ
  • JamesJ
Therefore the initial value problem y' = 2x, y(0) = 0, y(1) = 100 has no solution.
anonymous
  • anonymous
why does it have to be so opaque, but yet so simple.
JamesJ
  • JamesJ
it's not opaque now. That's why we do exercises! :-)

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