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anonymous
 4 years ago
Let f(x) = x**6.
f(1) =?
anonymous
 4 years ago
Let f(x) = x**6. f(1) =?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=x^6\]\[f(1)=(1)^6=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait if you got f(1)= 1 then can you show me how At x = 1, the slope of the tangent line to the graph =

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0basically find the slope I think

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yep. If you take the derivative of the general function, you will get a function that outputs the slope of the tangent line at input, x... Given that...\[f(x)=x^6\]Then...\[f'(x)=6x^5\]The slope at x = 1 is found by plugging 1 into the derivative of the function f(x)...\[f'(1)=6(1)^5=6\]
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