Let c be any constant number. Which of the following will always be perpendicular to −3x + y = −1?

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Let c be any constant number. Which of the following will always be perpendicular to −3x + y = −1?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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y equals one over three times x plus c y equals negative one over three times x plus c y equals negative three x plus c y equals three x plus c
Two perpendicular lines (neither horizontal or vertical) have slopes that multiply to -1. The given line −3x + y = −1 has a slope of 3. Place in y = mx + b form to get y = 3x -1. Look for a choice that has -1/3 as its slope. y equals negative one over three times x plus c which is y = (-1/3) (x) + c.

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