anonymous
  • anonymous
f(x) = 1/(x^5-4 x). Then f' =
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
f'= derivative of first times second minus derivative of second times first divided by the whole thing squared.
Xishem
  • Xishem
\[f(x)=\frac{1}{x^5-4x}\]We need to use the quotient rule...\[f'(x)=\frac{(x^5-4x)(0)-(1)(5x^4-4)}{(x^5-4x)^2}=\frac{5x^4-4}{(x^5-4x)^2}\]
anonymous
  • anonymous
what else do i need to do after that?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Xishem
  • Xishem
That's it. That's the derivative of f(x).
Directrix
  • Directrix
or f ' (x) =[ (4 - 5 x^4)] / [x^2 (x^4 -4) ^2]
Xishem
  • Xishem
Directrix is right. I forgot to distribute through the -1. My answer was wrong.

Looking for something else?

Not the answer you are looking for? Search for more explanations.