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anonymous

  • 4 years ago

f(x) = 1/(x^5-4 x). Then f' =

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  1. anonymous
    • 4 years ago
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    f'= derivative of first times second minus derivative of second times first divided by the whole thing squared.

  2. Xishem
    • 4 years ago
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    \[f(x)=\frac{1}{x^5-4x}\]We need to use the quotient rule...\[f'(x)=\frac{(x^5-4x)(0)-(1)(5x^4-4)}{(x^5-4x)^2}=\frac{5x^4-4}{(x^5-4x)^2}\]

  3. anonymous
    • 4 years ago
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    what else do i need to do after that?

  4. Xishem
    • 4 years ago
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    That's it. That's the derivative of f(x).

  5. Directrix
    • 4 years ago
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    or f ' (x) =[ (4 - 5 x^4)] / [x^2 (x^4 -4) ^2]

  6. Xishem
    • 4 years ago
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    Directrix is right. I forgot to distribute through the -1. My answer was wrong.

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