## anonymous 4 years ago How can you write the following using a radical sign and no negative exponents? 1. 3y^(2/5) 2. (3y)^(2/5) 3. a^(4/7) * b^(-4/7) 4. a^(1/10) * b^(-1/5)

1. anonymous

$3\sqrt[5]{y^2}$ is the first one

2. anonymous

second is $\sqrt[5]{3y^2}$

3. anonymous

explanations would be great if possible

4. anonymous

1.)$\ 3 \sqrt [5] {y^2}$2.)$\sqrt [5] {9y^2}$3.)$\sqrt [7] {a^4} * \sqrt [7] {\frac{1}{b^4}}$4.)$\sqrt [10] {a} * \sqrt [5] {\frac{1}{b}}$

5. anonymous

Here's an explanation for the first... $3y^{2/5}=3*y^{2/5}$Since the following is true...$y^{1/5}= \sqrt [5] {y}$The first statement is the same as...$3*y^{1/5}*y^{1/5}=3*\sqrt[5]{y}*\sqrt[5]{y}=3\sqrt[5]{y^2}$Does that make sense?

6. anonymous

yes! thank you:P