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Matt6288
 4 years ago
14ab^3/7a^2b^1
Matt6288
 4 years ago
14ab^3/7a^2b^1

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{14ab ^{3}}{7a ^{2}b ^{1}}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1The factors that are in the denominator have negative exponents (except for the 7) When you move them to the numerator, you change the exponents to positive.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{a ^{n}}=a ^{n}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{a}{a ^{2}}=a(a ^{2})=a ^{3}\]

Matt6288
 4 years ago
Best ResponseYou've already chosen the best response.0would it be a^6b^6c^2?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1And\[\frac{b ^{3}}{b ^{1}}=b ^{3}b ^{1}=b ^{4}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{a ^{3}b ^{3}c}{1^{3}b ^{3}c ^{1}}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1So the denominator contains 1^3?

Matt6288
 4 years ago
Best ResponseYou've already chosen the best response.0and my answer is A^6b^6c^2

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1yes. If that is a^3 in the denominator instead of 1^3
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