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anonymous

  • 4 years ago

3x^3y-3xy factor guys plz help here

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  1. Akshay_Budhkar
    • 4 years ago
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    is it\[3x^3y-3xy\] ?

  2. anonymous
    • 4 years ago
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    yes

  3. Akshay_Budhkar
    • 4 years ago
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    if yes take 3xy common so you have\[3xy(x^2-1)= 3xy(x-1)(x+1)\]

  4. anonymous
    • 4 years ago
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    ok thnx so much

  5. Akshay_Budhkar
    • 4 years ago
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    YW =D

  6. anonymous
    • 4 years ago
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    i have another one plz

  7. Akshay_Budhkar
    • 4 years ago
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    yea sure ask me

  8. anonymous
    • 4 years ago
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    x^4+4x+xy+4y

  9. Akshay_Budhkar
    • 4 years ago
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    \[x^4+4x+xy+4y\] is this it? or is it different?

  10. anonymous
    • 4 years ago
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    yes it is

  11. Akshay_Budhkar
    • 4 years ago
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    i feel u r missing something, this thing cant be factorized, do check it again

  12. Akshay_Budhkar
    • 4 years ago
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    see if it is 4x^3 instead of 4x

  13. anonymous
    • 4 years ago
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    no its not but i think its not possible cuz sometimes it could be not possible

  14. Akshay_Budhkar
    • 4 years ago
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    if you can write your answer as not possible then that is your answer

  15. anonymous
    • 4 years ago
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    ok i have this one 2x^4+x^2-6

  16. anonymous
    • 4 years ago
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    ok

  17. anonymous
    • 4 years ago
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    |dw:1328152090483:dw|

  18. anonymous
    • 4 years ago
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    thnx

  19. anonymous
    • 4 years ago
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    anytime

  20. Akshay_Budhkar
    • 4 years ago
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    \[\begin {array} 2u^2+u-6 \\ = 2u^2+4u-3u-6 \\ = 2u(u+4) - 3( u+4) \\ = (u+4)(2u-3) \\ = (x^2+4)(2x^2-3) \end {array}\] taking x^2=u

  21. Akshay_Budhkar
    • 4 years ago
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    ok i missed a "2"

  22. anonymous
    • 4 years ago
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    ok thnx and x^3-1

  23. Akshay_Budhkar
    • 4 years ago
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    LOL, are we solving a text book :P

  24. Akshay_Budhkar
    • 4 years ago
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    \[(x^3-1)=(x-1)(x^2+x+1)\] its a basic formula ^

  25. anonymous
    • 4 years ago
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    ok last two no cuz i have a test tmw

  26. anonymous
    • 4 years ago
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    srry if i am bothering u

  27. anonymous
    • 4 years ago
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    keep them coming lol

  28. anonymous
    • 4 years ago
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    lol

  29. anonymous
    • 4 years ago
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    k

  30. anonymous
    • 4 years ago
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    -6x^3+12x

  31. Akshay_Budhkar
    • 4 years ago
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    no no u ain't bothering me.. i am known for my patience =D

  32. anonymous
    • 4 years ago
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    |dw:1328152637369:dw|

  33. Akshay_Budhkar
    • 4 years ago
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    \[-6x^3+12x = -6x(x^2-2)=-6x(x+ \sqrt 2 ) ( x- \sqrt 2 )\]

  34. anonymous
    • 4 years ago
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    thnx guys and the last one is 5x+6-6x^2

  35. Akshay_Budhkar
    • 4 years ago
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    \[-(3x+2)(2x-3)\]

  36. Akshay_Budhkar
    • 4 years ago
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    \[ \begin {array} -(6x^2-5x-6) \\ -(6x^2-9x+4x-6) \\ - (3x(2x-3)+2(2x-3)) \\= -(3x+2)(2x-3) \end {array}\]

  37. Akshay_Budhkar
    • 4 years ago
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    you get it?

  38. anonymous
    • 4 years ago
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    from where did u get the 2x-3

  39. Akshay_Budhkar
    • 4 years ago
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    i took 3x common in the first two terms, then 2 common in the next two terms in step 2 to get 2x-3

  40. anonymous
    • 4 years ago
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    ohhh now i got it thnx so much... u really helped me a lot

  41. Akshay_Budhkar
    • 4 years ago
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    it is my pleasure =D

  42. anonymous
    • 4 years ago
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    :)))))))))))))

  43. anonymous
    • 4 years ago
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    k have a good day

  44. anonymous
    • 4 years ago
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    and thnx again

  45. Akshay_Budhkar
    • 4 years ago
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    *night . bye and all the best

  46. anonymous
    • 4 years ago
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    thnx u too

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