anonymous
  • anonymous
3x^3y-3xy factor guys plz help here
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Akshay_Budhkar
  • Akshay_Budhkar
is it\[3x^3y-3xy\] ?
anonymous
  • anonymous
yes
Akshay_Budhkar
  • Akshay_Budhkar
if yes take 3xy common so you have\[3xy(x^2-1)= 3xy(x-1)(x+1)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok thnx so much
Akshay_Budhkar
  • Akshay_Budhkar
YW =D
anonymous
  • anonymous
i have another one plz
Akshay_Budhkar
  • Akshay_Budhkar
yea sure ask me
anonymous
  • anonymous
x^4+4x+xy+4y
Akshay_Budhkar
  • Akshay_Budhkar
\[x^4+4x+xy+4y\] is this it? or is it different?
anonymous
  • anonymous
yes it is
Akshay_Budhkar
  • Akshay_Budhkar
i feel u r missing something, this thing cant be factorized, do check it again
Akshay_Budhkar
  • Akshay_Budhkar
see if it is 4x^3 instead of 4x
anonymous
  • anonymous
no its not but i think its not possible cuz sometimes it could be not possible
Akshay_Budhkar
  • Akshay_Budhkar
if you can write your answer as not possible then that is your answer
anonymous
  • anonymous
ok i have this one 2x^4+x^2-6
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1328152090483:dw|
anonymous
  • anonymous
thnx
anonymous
  • anonymous
anytime
Akshay_Budhkar
  • Akshay_Budhkar
\[\begin {array} 2u^2+u-6 \\ = 2u^2+4u-3u-6 \\ = 2u(u+4) - 3( u+4) \\ = (u+4)(2u-3) \\ = (x^2+4)(2x^2-3) \end {array}\] taking x^2=u
Akshay_Budhkar
  • Akshay_Budhkar
ok i missed a "2"
anonymous
  • anonymous
ok thnx and x^3-1
Akshay_Budhkar
  • Akshay_Budhkar
LOL, are we solving a text book :P
Akshay_Budhkar
  • Akshay_Budhkar
\[(x^3-1)=(x-1)(x^2+x+1)\] its a basic formula ^
anonymous
  • anonymous
ok last two no cuz i have a test tmw
anonymous
  • anonymous
srry if i am bothering u
anonymous
  • anonymous
keep them coming lol
anonymous
  • anonymous
lol
anonymous
  • anonymous
k
anonymous
  • anonymous
-6x^3+12x
Akshay_Budhkar
  • Akshay_Budhkar
no no u ain't bothering me.. i am known for my patience =D
anonymous
  • anonymous
|dw:1328152637369:dw|
Akshay_Budhkar
  • Akshay_Budhkar
\[-6x^3+12x = -6x(x^2-2)=-6x(x+ \sqrt 2 ) ( x- \sqrt 2 )\]
anonymous
  • anonymous
thnx guys and the last one is 5x+6-6x^2
Akshay_Budhkar
  • Akshay_Budhkar
\[-(3x+2)(2x-3)\]
Akshay_Budhkar
  • Akshay_Budhkar
\[ \begin {array} -(6x^2-5x-6) \\ -(6x^2-9x+4x-6) \\ - (3x(2x-3)+2(2x-3)) \\= -(3x+2)(2x-3) \end {array}\]
Akshay_Budhkar
  • Akshay_Budhkar
you get it?
anonymous
  • anonymous
from where did u get the 2x-3
Akshay_Budhkar
  • Akshay_Budhkar
i took 3x common in the first two terms, then 2 common in the next two terms in step 2 to get 2x-3
anonymous
  • anonymous
ohhh now i got it thnx so much... u really helped me a lot
Akshay_Budhkar
  • Akshay_Budhkar
it is my pleasure =D
anonymous
  • anonymous
:)))))))))))))
anonymous
  • anonymous
k have a good day
anonymous
  • anonymous
and thnx again
Akshay_Budhkar
  • Akshay_Budhkar
*night . bye and all the best
anonymous
  • anonymous
thnx u too

Looking for something else?

Not the answer you are looking for? Search for more explanations.