3x^3y-3xy factor guys plz help here

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3x^3y-3xy factor guys plz help here

Mathematics
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is it\[3x^3y-3xy\] ?
yes
if yes take 3xy common so you have\[3xy(x^2-1)= 3xy(x-1)(x+1)\]

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ok thnx so much
YW =D
i have another one plz
yea sure ask me
x^4+4x+xy+4y
\[x^4+4x+xy+4y\] is this it? or is it different?
yes it is
i feel u r missing something, this thing cant be factorized, do check it again
see if it is 4x^3 instead of 4x
no its not but i think its not possible cuz sometimes it could be not possible
if you can write your answer as not possible then that is your answer
ok i have this one 2x^4+x^2-6
ok
|dw:1328152090483:dw|
thnx
anytime
\[\begin {array} 2u^2+u-6 \\ = 2u^2+4u-3u-6 \\ = 2u(u+4) - 3( u+4) \\ = (u+4)(2u-3) \\ = (x^2+4)(2x^2-3) \end {array}\] taking x^2=u
ok i missed a "2"
ok thnx and x^3-1
LOL, are we solving a text book :P
\[(x^3-1)=(x-1)(x^2+x+1)\] its a basic formula ^
ok last two no cuz i have a test tmw
srry if i am bothering u
keep them coming lol
lol
k
-6x^3+12x
no no u ain't bothering me.. i am known for my patience =D
|dw:1328152637369:dw|
\[-6x^3+12x = -6x(x^2-2)=-6x(x+ \sqrt 2 ) ( x- \sqrt 2 )\]
thnx guys and the last one is 5x+6-6x^2
\[-(3x+2)(2x-3)\]
\[ \begin {array} -(6x^2-5x-6) \\ -(6x^2-9x+4x-6) \\ - (3x(2x-3)+2(2x-3)) \\= -(3x+2)(2x-3) \end {array}\]
you get it?
from where did u get the 2x-3
i took 3x common in the first two terms, then 2 common in the next two terms in step 2 to get 2x-3
ohhh now i got it thnx so much... u really helped me a lot
it is my pleasure =D
:)))))))))))))
k have a good day
and thnx again
*night . bye and all the best
thnx u too

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