## anonymous 4 years ago Simplify. Remember to use absolute-value notation when necessary. If a root cannot be simplified, state this. √9x²-30x+25

1. PaxPolaris

$\sqrt {\left( a-b \right)^2}= \left| a-b \right|$

2. anonymous

Yes this how far I got but when I turned it in I got this back

3. anonymous

√9x²-30x+25 9x^2 - 30x + 25 = (3x-5)^2 ; correct Square root of that will be +/- (3x-5). ; incorrect,

4. PaxPolaris

$\sqrt{9x²-30x+25}=\sqrt{\left( 3x \right)^2-2\cdot \left( 3x \right)\cdot5 + 5^2}=\sqrt{\left( 3x-5 \right)^2}$

5. PaxPolaris

the square root symbol only has non-negative roots. eg: $when\ a^2= 25 \implies a= \pm 5$ $but\ when\ a=\sqrt{25}; \implies a=+5$

6. PaxPolaris

so, $\huge\sqrt{\left( 3x-5 \right)^2}= \left| \left( 3x-5 \right) \right|$

7. anonymous

so that is the finally answer

8. PaxPolaris

yea, just with the abs. value sign

9. anonymous

ok thanks that really helped