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anonymous

  • 4 years ago

Simplify. Remember to use absolute-value notation when necessary. If a root cannot be simplified, state this. √9x²-30x+25

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  1. PaxPolaris
    • 4 years ago
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    \[\sqrt {\left( a-b \right)^2}= \left| a-b \right|\]

  2. anonymous
    • 4 years ago
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    Yes this how far I got but when I turned it in I got this back

  3. anonymous
    • 4 years ago
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    √9x²-30x+25 9x^2 - 30x + 25 = (3x-5)^2 ; correct Square root of that will be +/- (3x-5). ; incorrect,

  4. PaxPolaris
    • 4 years ago
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    \[\sqrt{9x²-30x+25}=\sqrt{\left( 3x \right)^2-2\cdot \left( 3x \right)\cdot5 + 5^2}=\sqrt{\left( 3x-5 \right)^2}\]

  5. PaxPolaris
    • 4 years ago
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    the square root symbol only has non-negative roots. eg: \[when\ a^2= 25 \implies a= \pm 5\] \[but\ when\ a=\sqrt{25}; \implies a=+5\]

  6. PaxPolaris
    • 4 years ago
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    so, \[\huge\sqrt{\left( 3x-5 \right)^2}= \left| \left( 3x-5 \right) \right|\]

  7. anonymous
    • 4 years ago
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    so that is the finally answer

  8. PaxPolaris
    • 4 years ago
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    yea, just with the abs. value sign

  9. anonymous
    • 4 years ago
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    ok thanks that really helped

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