anonymous
  • anonymous
A proton orbits a 1.0-cm-diameter metal ball 1.30 above the surface. The orbital period is 1.60 . what is the charge on the ball?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
i've done the calculations over and over and over and even did it without any rounding off. it's an online assignment, i'm about to tell my instructor that the answer it has is wrong cuz i don't see anything wrong in my calculations. all the units cancel and i answer with the unit it's asking for. anyone wanna verify? \[F=kq _{proton}q _{ball}/r ^{2}\] \[F=ma=mr \omega ^{2}=mr(2\pi/T)^{2}\] m=1.6*10^-16kg solve for q_ball. what am i doing wrong >:O
anonymous
  • anonymous
copy and paste took out units... that's 1.3mm and T is 1.6microseconds. i keep getting 4.28*10^-12 C
Shayaan_Mustafa
  • Shayaan_Mustafa
\[m=1.6*10^{-27}kg\] (for Proton)

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anonymous
  • anonymous
thx, that's what i did, i typed it wrong up there...so i still don't know what the problem is
Shayaan_Mustafa
  • Shayaan_Mustafa
are you there elica85?
anonymous
  • anonymous
yes!
Shayaan_Mustafa
  • Shayaan_Mustafa
so let us solve this
Shayaan_Mustafa
  • Shayaan_Mustafa
can post the procedure through which you found F?
anonymous
  • anonymous
it was on cramster http://www.cramster.com/solution/solution/1212303
anonymous
  • anonymous
it's the exact same problem since it's the solution for my text just different numbers. but i followed each step
Shayaan_Mustafa
  • Shayaan_Mustafa
ok ok. then there is one thing which could be the cause of wrong solutions. may be you typed wrong values in doing calculations. isn't it?
anonymous
  • anonymous
i checked so many times. T=1-6*10^-6s r=1.3*10^-3+.005=.0063m m=1.6*10^-27kg after setting each F equal to each other to solve for q_ball... \[q _{ball}=(4\pi mr )/T ^{2}*(4\pi \epsilon _{0}r ^{2})/q _{proton}\] =(4pi(1.6*10^-27)*.0063)/(1.6*10^-6)^2 * (4pi*8.85*10^-12*.0063^2)/(1.6*10^-19)
Shayaan_Mustafa
  • Shayaan_Mustafa
\[q=2.029*10^{-11}\]this is my answer.
Shayaan_Mustafa
  • Shayaan_Mustafa
you are making a complex. just relax and be easy. first find F and then plug it in law and then find q. This complex suits to professional. not for beginners like you and me.
anonymous
  • anonymous
all my chances were used up so it displayed the correct answer as being -4.47*10^-12 so i was close. i even tried with neg sign too :(
Shayaan_Mustafa
  • Shayaan_Mustafa
why -ve sign. huh? it is proton not electron. you first find force and reply me with your answer.
anonymous
  • anonymous
negative cuz the ball must be neg if it attracts the proton to orbit around it
Shayaan_Mustafa
  • Shayaan_Mustafa
no no. it is the charge of the ball that you want to find. while charge on proton is +ve. there are only two qs. one for ball and other for proton. for ball it is required, so no sign meant for it. for proton it is always +ve. Did you get my knowledge?
anonymous
  • anonymous
i think the question was probably to test the obvious. o well, i tried. if i get a B just for this one problem, i'll talk to the instructor cuz what i did should have worked. thx!
Shayaan_Mustafa
  • Shayaan_Mustafa
ok. as you wish and good luck. but kindly make your solution as easy as possible.

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