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 3 years ago
Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640.?
The chart below summarizes the 2008 population for five U.S. States.
U. S. State
2008 Population
Alaska
686,293
California
36,756,666
Hawaii
1,288,198
Idaho
1,523,816
Indiana
6,376,792
What is the probability that a randomly selected U.S. resident did not live in Alaska? Show step by step work. Round solution to the nearest thousandth
I got The probablility, P, that the person lives in alaska=Population of alaska divided by the U.S Population
P= 686,
 3 years ago
Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640.? The chart below summarizes the 2008 population for five U.S. States. U. S. State 2008 Population Alaska 686,293 California 36,756,666 Hawaii 1,288,198 Idaho 1,523,816 Indiana 6,376,792 What is the probability that a randomly selected U.S. resident did not live in Alaska? Show step by step work. Round solution to the nearest thousandth I got The probablility, P, that the person lives in alaska=Population of alaska divided by the U.S Population P= 686,

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andijo76
 3 years ago
Best ResponseYou've already chosen the best response.0oops P=686,293/303.824,640 = this as far as I got

PaxPolaris
 3 years ago
Best ResponseYou've already chosen the best response.1If that is the probability of the person being from Alaska.... The probability that the person is not from Alaska is \[{303,824,640686,293 \over 303,824,640}\ or\ 1{686,293/303,824,640}\]
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