A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
precal
 4 years ago
Assume f(3)=1 and f ' (3) = 4
Let g(x)=x^2 + f(x)
Find an equation of the line tangent to y=g(x) at x=3
precal
 4 years ago
Assume f(3)=1 and f ' (3) = 4 Let g(x)=x^2 + f(x) Find an equation of the line tangent to y=g(x) at x=3

This Question is Closed

precal
 4 years ago
Best ResponseYou've already chosen the best response.0what do you mean bookmark?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1g(x)=x^2+f(x) g(3)=3^2+f(3)=10 g'(x)=d(x^2)/dx + f'(x) [ sum rule] =2x+f'(x) g'(3)=2(3)+4=10 So can you find the tangent line at (3,g(3))=(3,10) ?

precal
 4 years ago
Best ResponseYou've already chosen the best response.0yes, m=10 and I will use the point (3,1) correct?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1since g(3)=10 (also), the point you need is (3,10)

precal
 4 years ago
Best ResponseYou've already chosen the best response.0y10=10(x3) y10=10x30 y=10x20 Tangent line
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.