## anonymous 4 years ago may any one help me in this exercise if p(t) = 9.865(1.025)^t find p'(t)

1. mathmate

hint: $$\frac{d\ a^t}{dt}\ = \ a^t \ ln(t)$$ set a=1.025 note that 9.865 is just a multiplicative constant.

2. anonymous

$\frac{d\ a^t}{dt}\ = \ a^t \ \ln(t)*t'$