## anonymous 4 years ago 1/(x^2-2)^3 differentiate with respect to x help plzzz

1. Rogue

Use the chain rule. $\frac {d}{dx} u^a = a u^{a-1} \frac {du}{dx}$$\frac {d}{dx} (x^2 - 2)^{-3} = -3(x^2 -2)^{-4} \frac {d}{dx} (x^2 - 2) = 2x * -3(x^2 -2)^{-4}$$\frac {d}{dx} (x^2 - 2)^{-3} = \frac {-6x}{(x^2 - 2)^4}$

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