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anonymous

  • 4 years ago

What is the integral(1/r^2-x^2)?

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  1. anonymous
    • 4 years ago
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    |dw:1328161407302:dw|

  2. anonymous
    • 4 years ago
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    \[\int\limits_{}^{}dx/(r^2-x^2)=\ln((x+r)/(x-r))/2r\]

  3. anonymous
    • 4 years ago
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    umm wld it make sense to say arcsin?

  4. anonymous
    • 4 years ago
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    arcsin is sin inverse right??? If it is then \[\int\limits_{}^{}1/\sqrt{r ^{2}-x ^{2}}\]=arcsin x.

  5. anonymous
    • 4 years ago
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    ohh good that is what i thought

  6. anonymous
    • 4 years ago
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    ohh i forgot the sqrt that is y i confused u lol

  7. anonymous
    • 4 years ago
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    Sorry

  8. anonymous
    • 4 years ago
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    Well if denominator is in a sqrt then you will get pi/2 as the answer....

  9. anonymous
    • 4 years ago
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    this good for an answer? 1/2a ln | r-x / r+x | + C

  10. anonymous
    • 4 years ago
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    i dont know

  11. anonymous
    • 4 years ago
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    lol No i needed the inverse sin one

  12. anonymous
    • 4 years ago
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    o :P

  13. anonymous
    • 4 years ago
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    whtvr I made a mistake and that y i got confused

  14. anonymous
    • 4 years ago
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    ok i no good in trig

  15. anonymous
    • 4 years ago
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    reg stuff i better

  16. anonymous
    • 4 years ago
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    but i just glance at it

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