A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
find the area bounded by the graph y = 4x^2 1, the x axis and the ordinates x = 1/2 and x=1
anonymous
 4 years ago
find the area bounded by the graph y = 4x^2 1, the x axis and the ordinates x = 1/2 and x=1

This Question is Closed

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4\[A = \int\limits_{1/2}^{1}(4x^{2} 1) dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0smartcow, i thought the ordinates were from 1/2 where did you get the 1/2 from?

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4well when i graphed it, the parabola from 1/2 to 1/2 is below the xaxis ?

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4is it bounded by the xaxis above or below ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328176928988:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328176997411:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so is the shaded the area? dw:1328177068433:dw

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4hmm i guess that makes more sense...why do they say it is bounded by the xaxis then

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but when i find the area i get 0 or maybe i have done some stupid error lemme check

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4no i get 0 as well, if the limits are 1/2 to 1

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4thats because the area under the xaxis is negative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer in my solution book says the answer is 4/3 square units

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4hmm well the area from 1/2 to 1 is 2/3 are you sure its not x=1 an x=1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0perhaps the answer in the solution book is wrong then or the question is wrong

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4dw:1328177655800:dw \[\int\limits_{1}^{1/2}(4x^{2} 1)dx + \int\limits_{1/2}^{1}(4x^{2} 1)dx = 2/3 + 2/3 = 4/3\] thats my best guess :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0WOAH!!!!!!!!!!!!!!!! that is brilliant thinking goodjob smartcow, thanks for the help greatly appreciated

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But the only solution for \( 4x^21\) is \(\pm\frac 12 \)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0genius what are you trying to say?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The parabola intersects the x axis at \(\pm \frac 12 \)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This question is not correct in my opinion.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i see, i think i support your opinion

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0See here, the area is not well defined : http://www.wolframalpha.com/input/?i=+y+%3D+4x%5E2+1%3Bx%3D1%2F2%3Bx%3D1%3Bx%3D0%3By%3D0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So I think dumcow's interpretation is not correct either.

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.4haha sorry i should have clarified , my drawing assumes the question is wrong at to get area of 4/3 the bounds must be x=1 and x=1 and xaxis

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no need to apologise! you have a case indeed hehehe

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But the bound x=1 and x=1 makes no sense right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am leaving now, take care :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0farewell genius, and thanks for the help once again !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.