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anonymous
 4 years ago
horizontal shift of:
240sin(4θ360)
and
4cos(1/2θ15)2.5
Please explain how you got those answers! Thanks :)
anonymous
 4 years ago
horizontal shift of: 240sin(4θ360) and 4cos(1/2θ15)2.5 Please explain how you got those answers! Thanks :)

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PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1If original is y= f(x) and final is, \[yk = a \cdot f(xh)\]or y = a⋅f(x−h) + k h is horizontal shift k is vertical shift a is stretch/ squish

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So in this case, 360 would be considered the horizontal shift, and it doesn't consist of a vertical shift?

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1+360 is horizontal shift from 240sin(4θ)

PaxPolaris
 4 years ago
Best ResponseYou've already chosen the best response.1if f(x) becomes f(xh) because now f(1) is moved to f(1+h) ... anyways if θ is in degrees it does not matter because 240sin(4θ360) will look exactly like 240sin(4θ)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So basically what ever h's sign is in the brackets, should be reversed? ex: 3cos(θ15) would be positive 15?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ahhh! Okay Thanks a lot!
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