1. anonymous

x=11/64

2. anonymous

Okay so, since neither the base nor the exponent is same, we take log log8^2x = log11 By rule of log, 2x.log8=log11 Or, 2x=log11/log8 So, 2x=1.153 x=1.153/2 x=0.576

3. anonymous

i would use this fact $b^x=A\iff x=\frac{ln(A)}{\ln(b)}$ to write $2x=\frac{\ln(11)}{\ln(2)}$ then divide by 2