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anonymous
 4 years ago
if tan^2(x) = sin^2(x)/cos^2(x) which by the half angle formulas = 1cos(2x)/1+cos(2x)...the 1/2's cancel... does that meant that tan^2(x)=1 or 0 or neither?
anonymous
 4 years ago
if tan^2(x) = sin^2(x)/cos^2(x) which by the half angle formulas = 1cos(2x)/1+cos(2x)...the 1/2's cancel... does that meant that tan^2(x)=1 or 0 or neither?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1neither, how do you figure it should be 1 or zero?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1\cos(2x)\div1+\cos(2x)\] take a 1 out of the top and you end up with \[(1+\cos(2x)\div1+\cos(2x)\]= 1? obviously this would be an identity if it were correct so i guess I'm just asking how it is wrong?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1+\cos(2x)}{1+\cos(2x)}\neq1\]check the algebra...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1\cos(2x)}{1+\cos(2x)}=\frac{\cos(2x)1}{1+\cos(2x)}\]but nothing is going to cancel here, so we just go round and round...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah I see. I think my lack of parenthesis made me see something that was not truly there. thank you.
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