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anonymous
 4 years ago
prove the trig functions
and show the steps
0=theta when i write this
6. sec0/tan0=csc0
7. (sec x +tan x)(1sin x/cos x)=1
8. 2/sqrt3 cosx+sinx=sec(pi/6x)
9. prove tan(0/2)=sin0/1+cos0 for 0 in quadrant 1 by filling in the reason belo
anonymous
 4 years ago
prove the trig functions and show the steps 0=theta when i write this 6. sec0/tan0=csc0 7. (sec x +tan x)(1sin x/cos x)=1 8. 2/sqrt3 cosx+sinx=sec(pi/6x) 9. prove tan(0/2)=sin0/1+cos0 for 0 in quadrant 1 by filling in the reason belo

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\sec \theta}{\tan \theta}=\csc \theta\] \[\frac{1}{\cos \theta}\over\frac{\sin \theta}{\cos \theta}\] \[(\frac{1}{\cos \theta})\times \cos \theta \over(\frac{\sin \theta}{\cos \theta} )\times \cos \theta\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{\sin \theta}=\csc \theta\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[(secx+tanx)(\frac{1sinx}{cosx})=1\] \[(\frac{1}{cosx}+\frac{sinx}{cosx})(\frac{1sinx}{cosx})\] \[\frac{1sinx}{\cos ^{2}x}+\frac{sinx\sin ^{2}x}{\cos ^{2}x}\] \[\frac{1sinx+sinx\sin ^{2}x}{\cos ^{2}x}\] \[\frac{1\sin ^{2}x}{\cos ^{2}x}\] \[\frac{\cos^2x}{\cos^2x}=1\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Can't tell what you mean by the third one. Don't know if sinx is part of the denominator or not.
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