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anonymous
 4 years ago
Find the general solution to
(b) dy/dt = t^2y^3
anonymous
 4 years ago
Find the general solution to (b) dy/dt = t^2y^3

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1this thing slow, or is it just me?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{dy}{y^3}=t^2dt\]Integrate both sides to get:\[\frac{1}{2y^2}=\frac{t^3}{3}+C\]Solve for y in terms of t.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1separables: \[\int \left(y^{3}dy=t^2dt\right)\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1thats what solving it will actually get you. If you cant remember how to integrate simple powers, then you might need to go back and review that.
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