## anonymous 4 years ago Find the general solution to (b) dy/dt = t^2y^3

1. amistre64

this thing slow, or is it just me?

2. anonymous

$\frac{dy}{y^3}=t^2dt$Integrate both sides to get:$\frac{-1}{2y^2}=\frac{t^3}{3}+C$Solve for y in terms of t.

3. amistre64

separables: $\int \left(y^{-3}dy=t^2dt\right)$

4. anonymous

what does y =?

5. amistre64

thats what solving it will actually get you. If you cant remember how to integrate simple powers, then you might need to go back and review that.