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Okay so, we take 2x common out from both numerator and denominator, so:
2x(x^2-x-12)/2x(x-4) = -1
Cancel 2x from both numerator and denominator so we get
x^2-x-12/x-4 = -1
Take x-4 to the other side and multiply by -1.
x^2 -x -12 =-x +4
Cancel -x from both sides since it is common.
x^2 -12 = 4
Take -12 to other side,
x^2 = 4+12
x^2 = 16
Or by taking square root:
x= 4 is the answer.
Now I know how to solve these type of problems.
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Im kind of struggling with this one, think you could help? ^^
(5x^3+20x^2-105x/5x^2-15x) = 0
Take 5x out common from numerator and denominator and cancel it. We now have:
x^2 +4x -21/x-3 =0
Remove the denominator because anything multiplied by 0 is 0.
So, x^2 +4x -21 = 0
x^2 +7x -3x -21= 0
(x+7)(x-3) = 0
x = -7 or x= 3
Brilliant! kk so I was on the right track xD
Thanks again dude