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anonymous
 4 years ago
If 0.275 moles of ferrous ammonium sulfate (Fe(NH4)2 *6H2O) nd an excess of all reagents are used in a synthesis of K3[Fe(C2O4)3]*3H2O, how many grams of the product will be obtained if the reaction gives a 100% yield. Show your work for full credit.
anonymous
 4 years ago
If 0.275 moles of ferrous ammonium sulfate (Fe(NH4)2 *6H2O) nd an excess of all reagents are used in a synthesis of K3[Fe(C2O4)3]*3H2O, how many grams of the product will be obtained if the reaction gives a 100% yield. Show your work for full credit.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In the molecular formulas of both there is one molecule of Fe hence the number of moles of the compoung will also be 0.275. Molecular weight: 3*39+56*3+(12*2+16*4)*9+3*(2+16). weight= number of moles *Molecular weight. Calculate it yourself.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I did use the molecular weight and calculated it but wanted to make sure it was correct. Thanks for the response though.
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