anonymous
  • anonymous
can anyone help me solve 2 problems with substitution? :)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
2 = 2y - x 23 = 5y - 4x
Rogue
  • Rogue
If you rearrange the first equation, you can get: x = 2y - 2 You can then plug that into the x in the second equation. 23 = 5y - 4(2y - 2) Then just solve that for y. After you get y, plug y back into x = 2y - 2 to get your x value. After you have both the x and y values, your done!
anonymous
  • anonymous
thank you! i got -12, -5

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Rogue
  • Rogue
Good job :)
anonymous
  • anonymous
& i also have a last problem like that
anonymous
  • anonymous
if you have time:)
Rogue
  • Rogue
Sure, hit me.
anonymous
  • anonymous
The measure of one acute angle in a right triangle is four times the measure of the acute angle. Write and solve a system of equations to find the measure of the acute angles.
Rogue
  • Rogue
Alright, so what do you know about the total degree measure of a triangle? The degree measure of a right angle?
anonymous
  • anonymous
180 & 90
Rogue
  • Rogue
Alright, good. Total angle measure = angle 1 + angle 2 + angle 3. 180 = 90 + angle 2 + angle 3 90 = angle 2 + angle 3 So the sum of the two acute angles is 90 degrees.
anonymous
  • anonymous
yess:)
Rogue
  • Rogue
If you let x = measure of the smaller acute angle, what is the measure of the bigger acute angle?
anonymous
  • anonymous
that's the part i don't understand.
Rogue
  • Rogue
Well, the bigger acute angle is 4 times as much as the smaller one. Small acute angle = x Big acute angle = 4x
Rogue
  • Rogue
And their sum is 90 degrees, so 90 = x + 4x
anonymous
  • anonymous
ohh!
Rogue
  • Rogue
You can do the rest right? :)
anonymous
  • anonymous
yes thank you!! :) i wish i had your brain lol
Rogue
  • Rogue
Haha, thanks, don't worry, you'll get there :)
anonymous
  • anonymous
and one more question, but short
anonymous
  • anonymous
x + 3 = y 3x + 4y = 7 so that would be; 3x + 4(x + 3) = 7 ?
Rogue
  • Rogue
Yep, nice :)
anonymous
  • anonymous
thanks! :)
Rogue
  • Rogue
For systems, just try to find a way to substitute one equation into the other.
anonymous
  • anonymous
Okay! thank you:D
Rogue
  • Rogue
Good luck with the rest, byes. :)
anonymous
  • anonymous
byee:)

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