anonymous
  • anonymous
Find the equation of the circle with center that passes through point A. center (1, 3) and point A (4, -2) equaling to 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
whats the equation of a generic circle?
anonymous
  • anonymous
(x-h)^2+(y-k)^2=r^2
anonymous
  • anonymous
Use the distance formula to find the radius

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amistre64
  • amistre64
good, now replace h with 1 and k with 3 for starters
amistre64
  • amistre64
the radius "r" is just the distance from the center to A
anonymous
  • anonymous
(x-1)^2+(y-3)^2=r^2 .....
amistre64
  • amistre64
good so far; now for "r"
amistre64
  • amistre64
do you recall the formula or any method to find the distance between 2 points?
anonymous
  • anonymous
yeahhhhh
amistre64
  • amistre64
then plug in the point for center and the point for A to determine the distance; thats your r then
amistre64
  • amistre64
i get 3 over and 5 down sooo; sqrt(3^2+5^2) = sqrt(34) perhaps?
amistre64
  • amistre64
and r^2 is then 34 (x-1)^2 + (y-3)^2 = 34 expand it all out and put all things to one side to zero it out
anonymous
  • anonymous
wait im not sure how to zero that out..
amistre64
  • amistre64
expand your ^2 terms
amistre64
  • amistre64
whats (x-1)^2 ?
anonymous
  • anonymous
x^2-1^2
amistre64
  • amistre64
not quite, (x-1)(x-1) = x^2 -2x +1
amistre64
  • amistre64
expand the (y-3)^2
anonymous
  • anonymous
y^2-6^2+3
amistre64
  • amistre64
.... youre really bad at that :) y-3 y-3 ---- y^2 -3y -3y+9 ---------- y^2 -6y + 9
amistre64
  • amistre64
sooo: x^2 -2x +1 + y^2 -6y +9 = 34 combine the constants x^2 -2x + y^2 -6y +10 = 34 and -34 from each side x^2 -2x + y^2 -6y +10 = 34 -34 -34 --------------------------- x^2 -2x + y^2 -6y - 24 = 0
anonymous
  • anonymous
gochaaa , thanks!
amistre64
  • amistre64
good luck :)

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