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anonymous
 4 years ago
Jim has received scores of 74and 80 on his first two 100 point tests. What score must he get on his third 100 point test to keep an average of 83 or greater?
Third test >= 'blank' (If the average is greater then the possible number of points, enter DNE)
anonymous
 4 years ago
Jim has received scores of 74and 80 on his first two 100 point tests. What score must he get on his third 100 point test to keep an average of 83 or greater? Third test >= 'blank' (If the average is greater then the possible number of points, enter DNE)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so (74 + 80 + x)/3 = 83  does that make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So do I divide the three then?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You're right myin, but since we know the limit, 100  aren't we just finding the minimum number that will give you an 83 average? Or am I reading/doing this wrong?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lulu, you multiply both sides of the equation by 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(Which gets rid of the /3 portion on the left)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer doesn't have to be 83, it can be a higher average

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0we want the average to be greater than or equal to 83 so we have \[\frac{74+80+x}{3} \text { is the average } \] we want \[\frac{74+80+x}{3} \text{ we want this to be greater than or equal to 83} \] symbolically this looks like \[\frac{74+80+x}{3} \ge 83 \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0but once you get x=100 you could have also wrote x>=100 in the end so your way would have worked fine i just like my equations/inequalities read like my sentences

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0that was an example by the way with the x=100

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0i didn't solve this sorry lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, I have a question that might be a bit silly. How do I work with the division of the equation. For the life of me I can't remember how to work an equation like that.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hey lulu  sorry I stepped away for a bit  so your question is regarding how to deal with the division of the equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes, I'm not sure how to do it. Haven't covered it in a while and I can't remember how to go about it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No problem! So, the rule of thumb is when you multiply/divide, you need to do the same thing to both sides of the equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, in our case, you want to multiply both sides of the equation by 3, like this: \[(74 + 80 + x)/3 *3 = 83 * 3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oooh I get it, thank you so much!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Awesome  thanks for sticking with me, I got confused myself there for a bit :P. And sorry for going quiet for a bit there  great work lulu, thanks!
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