Jim has received scores of 74and 80 on his first two 100 point tests. What score must he get on his third 100 point test to keep an average of 83 or greater? Third test >= 'blank' (If the average is greater then the possible number of points, enter DNE)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Jim has received scores of 74and 80 on his first two 100 point tests. What score must he get on his third 100 point test to keep an average of 83 or greater? Third test >= 'blank' (If the average is greater then the possible number of points, enter DNE)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Ok, so (74 + 80 + x)/3 = 83 - does that make sense?
inequality
So do I divide the three then?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

You're right myin, but since we know the limit, 100 - aren't we just finding the minimum number that will give you an 83 average? Or am I reading/doing this wrong?
Lulu, you multiply both sides of the equation by 3
(Which gets rid of the /3 portion on the left)
the answer doesn't have to be 83, it can be a higher average
we want the average to be greater than or equal to 83 so we have \[\frac{74+80+x}{3} \text { is the average } \] we want \[\frac{74+80+x}{3} \text{ we want this to be greater than or equal to 83} \] symbolically this looks like \[\frac{74+80+x}{3} \ge 83 \]
but once you get x=100 you could have also wrote x>=100 in the end so your way would have worked fine i just like my equations/inequalities read like my sentences
that was an example by the way with the x=100
i didn't solve this sorry lol
So, I have a question that might be a bit silly. How do I work with the division of the equation. For the life of me I can't remember how to work an equation like that.
Hey lulu - sorry I stepped away for a bit - so your question is regarding how to deal with the division of the equation?
Yes, I'm not sure how to do it. Haven't covered it in a while and I can't remember how to go about it.
No problem! So, the rule of thumb is when you multiply/divide, you need to do the same thing to both sides of the equation.
So, in our case, you want to multiply both sides of the equation by 3, like this: \[(74 + 80 + x)/3 *3 = 83 * 3\]
Oooh I get it, thank you so much!
Awesome - thanks for sticking with me, I got confused myself there for a bit :P. And sorry for going quiet for a bit there - great work lulu, thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question