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Kris5
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Help please: Use the distance formula to show that the triangle ABC, with vertices A(1,2),B(3,2), and C(1,4), is a right triangle. Explain your reasoning.
 2 years ago
 2 years ago
Kris5 Group Title
Help please: Use the distance formula to show that the triangle ABC, with vertices A(1,2),B(3,2), and C(1,4), is a right triangle. Explain your reasoning.
 2 years ago
 2 years ago

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lauriy Group TitleBest ResponseYou've already chosen the best response.1
AB(4; 4) BC(2; 2) AC(2; 6) Length of AB = sqrt(4^2 + 4^2) = sqrt(32) = 4sqrt(2) Length of BC = sqrt(2^2 + 2^2) = sqrt(8) = 2sqrt(2) Length of AC = sqrt(2^2 + 6^2) = sqrt(40) = 2sqrt(10) According to pythagoras a^2 + b^2 = c^2 if it's a right triangle. 4sqrt(2) + 2sqrt(2) = 2sqrt(10) 32 + 8 = 40 And that is true. Win.
 2 years ago

Kris5 Group TitleBest ResponseYou've already chosen the best response.0
Thank you. So basically, you find the distance between AB,BC, and AC. Then you plug it in the a2+b2=c2 formula?
 2 years ago

lauriy Group TitleBest ResponseYou've already chosen the best response.1
Since you can only use the distances I can't really see another way. So yeah, 'a^2 + b^2 = c^2 must be true for right triangles' is basically all you need to explain imo : )
 2 years ago

Kris5 Group TitleBest ResponseYou've already chosen the best response.0
okay, thanks.
 2 years ago
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