Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Kris5

  • 4 years ago

Help please: Use the distance formula to show that the triangle ABC, with vertices A(-1,-2),B(3,2), and C(1,4), is a right triangle. Explain your reasoning.

  • This Question is Closed
  1. lauriy
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    AB(4; 4) BC(-2; 2) AC(2; 6) Length of AB = sqrt(4^2 + 4^2) = sqrt(32) = 4sqrt(2) Length of BC = sqrt(-2^2 + 2^2) = sqrt(8) = 2sqrt(2) Length of AC = sqrt(2^2 + 6^2) = sqrt(40) = 2sqrt(10) According to pythagoras a^2 + b^2 = c^2 if it's a right triangle. 4sqrt(2) + 2sqrt(2) = 2sqrt(10) 32 + 8 = 40 And that is true. Win.

  2. Kris5
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you. So basically, you find the distance between AB,BC, and AC. Then you plug it in the a2+b2=c2 formula?

  3. lauriy
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Since you can only use the distances I can't really see another way. So yeah, 'a^2 + b^2 = c^2 must be true for right triangles' is basically all you need to explain imo : )

  4. Kris5
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, thanks.

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy