pokemon23
  • pokemon23
Factor again the expression
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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pokemon23
  • pokemon23
|dw:1328231408045:dw|
pokemon23
  • pokemon23
would the answer be
anonymous
  • anonymous
they both have x in common so...

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More answers

pokemon23
  • pokemon23
|dw:1328231433797:dw|
anonymous
  • anonymous
yep!
pokemon23
  • pokemon23
yes I'm getting the hang of it
pokemon23
  • pokemon23
thanks meidrik and Hero
anonymous
  • anonymous
sure thing
pokemon23
  • pokemon23
|dw:1328231509108:dw|
Hero
  • Hero
What did I do? I didn't do anything :P
anonymous
  • anonymous
It was your presence
Hero
  • Hero
All I did was show up :P
pokemon23
  • pokemon23
do we find facor in this question for this question
anonymous
  • anonymous
they have a 6 in common so take that out
pokemon23
  • pokemon23
|dw:1328231568890:dw|
anonymous
  • anonymous
6(2x-r)
Hero
  • Hero
You find something that you can divide by both terms evenly
pokemon23
  • pokemon23
I don't get it,,?
pokemon23
  • pokemon23
So we divide 12 by 3 or 2..?
anonymous
  • anonymous
by 6
anonymous
  • anonymous
you divide by what you have in common
pokemon23
  • pokemon23
|dw:1328231685504:dw|
anonymous
  • anonymous
right, but it isnt simplified because they still have a 3 in common
pokemon23
  • pokemon23
|dw:1328231766372:dw|
Hero
  • Hero
|dw:1328231645628:dw|
anonymous
  • anonymous
no, 2(6x - 3r), factor a 6 OUT (2)(6)(2x - r) = 12(2x-r)
Hero
  • Hero
mridrik, I was referring to the previous problem, not this one.
anonymous
  • anonymous
I was talking to the other guy
Hero
  • Hero
oops
pokemon23
  • pokemon23
lost?
Hero
  • Hero
bad timing on your post
anonymous
  • anonymous
yeah
anonymous
  • anonymous
(Talking to pokemon) still stuck?
pokemon23
  • pokemon23
let me relog out then reconnect..
pokemon23
  • pokemon23
ok back I'm stuck lets go step by step
anonymous
  • anonymous
so which one are we on again?
pokemon23
  • pokemon23
|dw:1328232239409:dw|
anonymous
  • anonymous
They are both divisible by 6, so divide by 6 6(2x - r)
pokemon23
  • pokemon23
would it be 2t
anonymous
  • anonymous
look at what i wrote
pokemon23
  • pokemon23
ya but in this question the variable consist of a t
anonymous
  • anonymous
I thought it was an x
pokemon23
  • pokemon23
lol go to my next question I posted

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