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would the answer be
they both have x in common so...
yes I'm getting the hang of it
thanks meidrik and Hero
What did I do? I didn't do anything :P
It was your presence
All I did was show up :P
do we find facor in this question for this question
they have a 6 in common so take that out
You find something that you can divide by both terms evenly
I don't get it,,?
So we divide 12 by 3 or 2..?
you divide by what you have in common
right, but it isnt simplified because they still have a 3 in common
no, 2(6x - 3r), factor a 6 OUT (2)(6)(2x - r) = 12(2x-r)
mridrik, I was referring to the previous problem, not this one.
I was talking to the other guy
bad timing on your post
(Talking to pokemon) still stuck?
let me relog out then reconnect..
ok back I'm stuck lets go step by step
so which one are we on again?
They are both divisible by 6, so divide by 6 6(2x - r)
would it be 2t
look at what i wrote
ya but in this question the variable consist of a t
I thought it was an x
lol go to my next question I posted