anonymous
  • anonymous
I need help with 1+42^13=
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Is this estimating?
anonymous
  • anonymous
1265437718438866624513?
anonymous
  • anonymous
well here is the original problem

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anonymous
  • anonymous
Let g(x)= -x^(-2) + 6x^14 + pi^7. Find g'(0.5).
anonymous
  • anonymous
and I got to..
anonymous
  • anonymous
Yay you go me to level 6 woot!
amistre64
  • amistre64
clean up the replies please ....
anonymous
  • anonymous
g(x)= 2(0.5)^-3+84(0.5)^13
anonymous
  • anonymous
Who was that redirrected towards ?
amistre64
  • amistre64
looks like something for a calculator :)
amistre64
  • amistre64
yes, it was.
anonymous
  • anonymous
So you get a derived function: 2x + 84x^13 + 7pi And now: 2(0.5) + 42 * 0.5^13 + 7pi = 22.99628... Ce'nest pa?
anonymous
  • anonymous
Yes it sure does Amistre64 my caculator messed up a bit :P i thought i was messed up
anonymous
  • anonymous
1+42^13
amistre64
  • amistre64
:) i tend to use the wolf for those things .... makes life simpler on the cuticles
anonymous
  • anonymous
what is the owlf?
anonymous
  • anonymous
wolf
amistre64
  • amistre64
www.wolframalpha.com
amistre64
  • amistre64
its a math calculator that does all sorts of neat things
anonymous
  • anonymous
oh I tried that and it was giving me the def. of find
anonymous
  • anonymous
Lol i use my Chemistry one my boss gave me :P
anonymous
  • anonymous
what is it ?
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=derivative+-x%5E%28-2%29+%2B+6x%5E14+%2B+pi%5E7
amistre64
  • amistre64
then we can take that derivative part and plug in /5
amistre64
  • amistre64
.5
anonymous
  • anonymous
wait I look at the first result is that it ? (84 x^16+2)\/x^3
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=%2884+x%5E16%2B2%29%2Fx%5E3+%2C+x%3D.5
amistre64
  • amistre64
yes, simplified of course
anonymous
  • anonymous
ahh you made it look so easy
amistre64
  • amistre64
:)

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